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I am looking to build my own box for 2 10" JL audio Subs, they say they need 3/4 of a cubic foot, but that sounds kind of small to me...
how much air should I give these things? and does anyone know how I will determine the dimentions of my box? I have never done this before, any help would be awesome...

I also want to mount my amp on top of the box, anyone have any ideas on how I might build a small compartment for it while building the box? going to try to make this sound good and look clean..

-Michael

 
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if they say use .75^3 ft then use it.

lets use my box for example its 16" x 16" x 12" on the out side, take all those minius the the thickness of the wood 3/4 " on each side so i need to take off 1.5 " to all of my demensions then multiply

14.5 x 14.5 x 10.5 = 2207.xxxxx then divide that by 1728 (12x12x12) so 2207.xxx/1728 = 1.27ft^3 that is before displacement


there ya go

ps i only have 1 sub so my dimensions will be different than yours, also make sure you have 2 different chambers. not a single chamber box for 2 woofers

 
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go to rockfordfosgate.com then go to rf tech or any other company should have a form that figures it out for you or you can just use the regular formula

 
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Whcih JL 10s?.. W3's W0's?.. if W3's which ohm versions?..

 
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this guy has been PMing me alot, he doesnt have them yet, and hasnt decided yet.

id go for 10w3-D4's, can be wired for a 4 ohm load, can take a decent amount of power, and would give you a very nice output at 2-3 cubes sealed depending on how deep/tight you want it to play.

can be in less than 2 cubes total too, but id worry about it being a bit boomy at that point, even with the polyfill.