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Old 12-23-2003   #1 (permalink)
Skunk2ner
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rotional weight theory...

ok, so upon doing a search i've realized the stock steel rim (which i am running currently) is 21 lbs... so if i were to purchase these enkei rims that each weigh 9.5 lbs (15"), that would be saving myself 46 lbs of rotational weight.

chopping off 10 lbs. of weight from wheels/brakes/etc, non-suspended components, in theory will shave .01 second off your 1/4th mile time... so i've i'm saving 46 lbs. that should be around .046 seconds off my 1/4th??

also, i believe that rotational weight will save you even more than regular unsprung weight... hmm

interesting... i should run her before and after to test this theory...



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Last edited by Skunk2ner; 12-23-2003 at 03:49 AM.
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Old 12-23-2003   #2 (permalink)
jdmb16ahatch
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uhhh i duno if the theory is correct because there is no formula for rotational mass but yeh less weight means less rotational mass, which in turn is less power needed to move the car and less stress on the engine...
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Old 12-23-2003   #3 (permalink)
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this has been covered before....

where is zzyzx or boilermaker1
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Old 12-23-2003   #4 (permalink)
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we went over this before
who told you that every 10LBS lost of rotational wight = .01 sec????


However the article did not cover how unsprung weight affected handling. If you are in to autocross or track days, a lower unsprung weight emensly helps handling (Because the suspension can deal more with controling the car rather then trying to keep the tires on the ground...)
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Old 12-23-2003   #5 (permalink)
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Quote:
Originally posted by Zzyzx
we went over this before
who told you that every 10LBS lost of rotational wight = .01 sec????

sorry, i did a search and didn't see that one for some reason...

also, i read in the suspension forum that cutting back 10 lbs. of unsprung weight will save you the .01 in the 1/4th. it was just something i was pondering.
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